The power supply to SCHMITTINVEE is reversed. Look at the +/- polarity labels on the inverter and on the power supply, V1, pins. Before attempting simulation in EasyEDA, you must also read the Simulation Tutorial (3), in (2) in: [https://easyeda.com/forum/topic/How-to-ask-for-help-and-get-an-answer-71b17a40d15442349eaecbfae083e46a](https://easyeda.com/forum/topic/How-to-ask-for-help-and-get-an-answer-71b17a40d15442349eaecbfae083e46a) In particular you will find the section (9) on **Initial conditions and starting up circuits** helpful. BTW, before you correct your mistake, you look at the current drawn through V1, that will show you a huge current. That huge current should tell you that there is something wrong with your circuit.  In a real circuit, that huge current would burn out the device, giving a visual and olfactory indication that something is wrong. :)

Although it is usually less important in a simulation (because power supplies are often assumed to be ideal), you might like to read about the importance of power supply decoupling: [https://easyeda.com/forum/topic/UPDATED-Power-supply-decoupling-and-why-it-matters-30a39d0a77f34d5d8dc77e37c035b3d3](https://easyeda.com/forum/topic/UPDATED-Power-supply-decoupling-and-why-it-matters-30a39d0a77f34d5d8dc77e37c035b3d3)

Using your recommendations and with the help of the document you provided i came up with a circuit but when i start the simulation i get a gateway timeout error. I think its the pulse times that dont let me run the simulation but i cant get it right. 

No matter i found the problem it was the capacitance value. Thanks for your help and the documents you provided helped me a lot to understand things i could never think of.

For info: The circuit you have made is an unusual configuration. Normally R1 is placed in parallel with D1. Also, you can change the duty cycle by adding a resistor, R2, in series with D1. In that case, R1 is connected across the series pair of D1 and R2. You can make the rise and fall times completely independent by adding a second diode, D2 in series with R1. D2 has to be connected in the opposite direction to D1. :)